🌕 102. 二叉树的层序遍历

难度: 🌕

问题描述

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解法

/**
 * Definition for a binary tree node.
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode() {}
 *     TreeNode(int val) { this.val = val; }
 *     TreeNode(int val, TreeNode left, TreeNode right) {
 *         this.val = val;
 *         this.left = left;
 *         this.right = right;
 *     }
 * }
 */
class Solution {
    public List<List<Integer>> levelOrder(TreeNode root) {
        // 思路：
        // 辅助 队列
        List<List<Integer>> res = new ArrayList<>();
        Queue<TreeNode> queue = new LinkedList<>();
        if(root == null) {
            return res;
        }
        // root != null
        queue.offer(root);
        while(!queue.isEmpty()) {
            int len = queue.size();
            List<Integer> list = new ArrayList<>();
            for(int i = 0; i < len; i ++) {
                TreeNode cur = queue.poll();
                list.add(cur.val);
                if(cur.left != null) {
                    queue.offer(cur.left);
                }
                if(cur.right != null) {
                    queue.offer(cur.right);
                }
            }
            res.add(list);
        }
        return res;
    }
}

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输出