🌗 剑指 Offer 47. 礼物的最大价值

难度: 🌗

问题描述

---

解法

class Solution {
    public int maxValue(int[][] grid) {
        // 思路：
        // dp[i][j]
        int row = grid.length;
        int col = grid[0].length;
        int[][] dp = new int[row][col];
        dp[0][0] = grid[0][0];
        for(int i = 1; i < row; i ++) {
            dp[i][0] = dp[i - 1][0] + grid[i][0];
        }
        for(int j = 1; j < col; j ++) {
            dp[0][j] = dp[0][j - 1] + grid[0][j];
        }
        for(int i = 1; i < row; i ++) {
            for(int j = 1; j < col; j ++) {
                dp[i][j] = Math.max(dp[i - 1][j], dp[i][j - 1]) + grid[i][j];
            }
        }
        return dp[row - 1][col - 1];
    }
}

---

输出